FeCl₃ Test for Phenol

FeCl₃ Test for Phenol

Purpose: Used to identify phenols.

Reaction:3C6H5OH+FeCl3→Fe(OC6H5)3+3HCl3C_6H_5OH + FeCl_3 \rightarrow Fe(OC_6H_5)_3 + 3HCl

Phenol reacts with neutral FeCl₃ to form a ferric phenoxide complex, producing a violet/purple colour.

Observation: Violet colour → Phenol present

JEE/NEET point:
The test is due to formation of a coloured complex, not simply an acid–base reaction.

Example:C6H5OH→FeCl3violet complexC_6H_5OH \xrightarrow{FeCl_3} \text{violet complex}

Note: Some other compounds containing suitable groups can also give colours with FeCl₃, so the test is not absolutely specific for phenol.

Other Tests for Phenol (JEE/NEET)

S. No.TestReagentObservation
1Bromine water testBr2/H2OBromine water decolourises and a white precipitate of 2,4,6-tribromophenol forms.
2Liebermann’s nitroso testNaNO2+conc.H2SO4Deep blue/green colour; on dilution, red colour may appear, and on adding alkali, blue/green colour returns.
3Azo dye testBenzene diazonium chloride in alkaline mediumAn orange/red azo dye forms.
4Phthalein dye testPhthalic anhydride + conc. H2SO4 followed by NaOHPink colour develops due to formation of phenolphthalein in alkaline medium.
5Ferric chloride testNeutral FeCl3 solutionViolet, blue, green or other characteristic colour may develop, depending on the compound.

Important reactions

1. Bromine water test

Product: 2,4,6-tribromophenol (white precipitate).

2. Azo dye test

Phenol reacts with benzene diazonium chloride in alkaline medium to form an orange-red azo dye.

NEET quick revision: Remember FeCl₃ → violet colour, bromine water → white precipitate, and azo dye test → orange/red dye.

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