JEE/NEET CHEMISTRY — 50 MARKS
Time: 60 Minutes
Maximum Marks: 50
SECTION A — MCQs
20 × 1 = 20 marks
1. Which of the following is the correct order of acidic strength in aqueous medium?
A. H₂O > CH₃OH > NH₃
B. CH₃OH > H₂O > NH₃
C. NH₃ > H₂O > CH₃OH
D. H₂O > NH₃ > CH₃OH
2. The noble gas configuration of phosphorus (Z = 15) is:
A. [Ne] 3s² 3p³
B. [He] 2s² 2p⁶ 3s² 3p³
C. [Ar] 3s² 3p³
D. [Ne] 3s² 3p⁵
3. An element having electronic configuration [Ne] 3s² 3p⁵ belongs to:
A. Group 15, Period 3
B. Group 17, Period 3
C. Group 17, Period 2
D. Group 7, Period 3
4. Which group shows the strongest +R effect?
A. –NO₂
B. –COOH
C. –NH₂
D. –CN
5. The reagents used in the Gattermann–Koch reaction are:
A. CO + HCl/AlCl₃, CuCl
B. CO₂ + HCl/AlCl₃
C. CO + Cl₂/FeCl₃
D. HCN + HCl/AlCl₃
6. Which ligand is strongest according to the spectrochemical series?
A. Cl⁻
B. F⁻
C. NH₃
D. CN⁻
7. Reimer–Tiemann reaction of phenol with CHCl₃/NaOH gives mainly:
A. Benzaldehyde
B. Salicylaldehyde
C. Benzoic acid
D. Toluene
8. The major product of Kolbe’s reaction of sodium phenoxide followed by acidification is:
A. Benzoic acid
B. Salicylic acid
C. Phenol
D. Benzaldehyde
9. A secondary amine reacts with nitrous acid to form:
A. Nitroalkane
B. N-nitrosoamine
C. Alcohol
D. Alkene
10. The equivalent weight of H₂SO₄ in an acid-base reaction is:
A. 98
B. 49
C. 24.5
D. 196
11. For a hydrogen-like atom, the energy of an electron in orbit n is proportional to:
A. n²
B. 1/n
C. –1/n²
D. –n²
12. The correct order of dipole moment is:
A. HF > HCl > HBr > HI
B. HI > HBr > HCl > HF
C. HCl > HF > HBr > HI
D. HF > HI > HBr > HCl
13. A reaction in which two species undergo oxidation-state changes to produce a species having an intermediate oxidation state is called:
A. Disproportionation
B. Comproportionation
C. Neutralisation
D. Hydrolysis
14. Which pair represents structural isomers?
A. cis-2-butene and trans-2-butene
B. n-butane and isobutane
C. (R)-2-butanol and (S)-2-butanol
D. cis-2-butene and 2-butene
15. Which alkane conformation is the most stable?
A. Eclipsed
B. Fully eclipsed
C. Staggered
D. Partially eclipsed
16. Ozonolysis of propene followed by reductive work-up gives:
A. Methanal + ethanal
B. Methanal + methanol
C. Ethanal + ethanol
D. Acetone + methanal
17. Which statement is correct for an SN2 reaction?
A. It proceeds through carbocation formation
B. Rate depends only on substrate concentration
C. It involves backside attack
D. It is favoured by tertiary alkyl halides
18. Acid chlorides react with water to produce:
A. Alcohol
B. Aldehyde
C. Carboxylic acid
D. Ether
19. Hydration of a terminal alkyne in the presence of HgSO₄/H₂SO₄ ultimately gives:
A. Primary alcohol
B. Aldehyde
C. Ketone
D. Ether
20. The reaction of an alkene with cold, dilute alkaline KMnO₄ is commonly used as:
A. Baeyer test
B. Tollens’ test
C. Fehling’s test
D. Lucas test
SECTION B — STATEMENT / CONCEPT
10 × 2 = 20 marks
21. Consider the following statements about SN1 and SN2 reactions:
- SN1 reactions involve carbocation formation.
- SN2 reactions proceed through a single-step mechanism.
- SN1 is generally favoured by tertiary substrates.
- SN2 reactions show retention of configuration.
Which statements are correct?
A. 1, 2 and 3 only
B. 1 and 4 only
C. 2 and 3 only
D. All four
22. For a zero-order reaction, the time required for complete consumption of reactant is finite, whereas for a first-order reaction, complete consumption theoretically requires infinite time.
If the half-life of a first-order reaction is 20 min, the time required for 75% completion is:
A. 20 min
B. 30 min
C. 40 min
D. 60 min
23. HBr adds to propene in the presence of peroxide.
Answer the following:
(i) State the major product.
(ii) Name the rule responsible for this orientation.
(iii) Why does this reaction proceed through a radical mechanism?
24. Match the following:
| Reaction | Product/feature |
|---|---|
| A. Clemmensen reduction | 1. Zn(Hg)/HCl |
| B. Wolff–Kishner reduction | 2. NH₂NH₂/KOH |
| C. Cannizzaro reaction | 3. Aldehydes without α-H |
| D. Aldol reaction | 4. Aldehydes/ketones having α-H |
Choose the correct matching.
25. Give the products obtained in the following tests:
(i) Alkene + Br₂/CCl₄
(ii) Terminal alkyne + ammoniacal AgNO₃
(iii) Alkene + cold alkaline KMnO₄
26. A Grignard reagent reacts with a nitrile followed by hydrolysis.
(i) Write the general reaction.
(ii) What class of compound is obtained?
(iii) What happens to the nitrile carbon?
27. Complete the following reactions:
(i) CH₃CH₂Br + alc. KOH → ?
(ii) CH₃CH₂Br + aq. KOH → ?
(iii) CH₃CH₂OH —conc. H₂SO₄, 443 K→ ?
28. Complete the following reactions:
(i) 2CH₃CHO + dilute NaOH → ?
(ii) 2C₆H₅CHO + concentrated NaOH → ?
Name both reactions.
29. An ideal gas expands from V₁ to V₂.
Write the expression for work done when expansion is:
(i) Reversible and isothermal
(ii) Against constant external pressure
30. Define the following:
(i) Heat capacity
(ii) Specific heat capacity
(iii) Molar heat capacity
Also write the relationship between heat supplied and temperature change.
SECTION C — NUMERICAL / JEE-LEVEL
5 × 2 = 10 marks
31. The enthalpy change of a reaction at constant pressure is –50 kJ mol⁻¹. If the reaction involves gaseous reactants and products, explain why ΔH and ΔU may differ. Write the relation between ΔH and ΔU for gaseous reactions.
32. Calculate the heat required to raise the temperature of 200 g of water from 25°C to 75°C, given:
Specific heat of water = 4.2 J g⁻¹ K⁻¹.
33. The enthalpy of neutralisation of a strong acid by a strong base is approximately:
A. +57.1 kJ mol⁻¹
B. –57.1 kJ mol⁻¹
C. –5.71 kJ mol⁻¹
D. +5.71 kJ mol⁻¹
Explain the reason for its nearly constant value.
34. Using Hess’s law:
C + ½O₂ → CO ΔH = –110.5 kJ mol⁻¹
CO + ½O₂ → CO₂ ΔH = –283.0 kJ mol⁻¹
Calculate ΔH for:
C + O₂ → CO₂
35. For the reaction:
N₂(g) + 3H₂(g) → 2NH₃(g)
Predict the sign of ΔS and explain your answer.
BONUS JEE/NEET REACTION REVISION
Before attempting the paper, revise these high-yield reaction pairs:
- Reimer–Tiemann: Phenol → salicylaldehyde
- Kolbe–Schmitt: Phenol → salicylic acid
- Gattermann–Koch: Benzene → benzaldehyde
- Clemmensen: C=O → CH₂ using Zn(Hg)/HCl
- Wolff–Kishner: C=O → CH₂ using NH₂NH₂/KOH
- Cannizzaro: Aldehyde without α-H → alcohol + carboxylate
- Aldol: Carbonyl compound with α-H → β-hydroxy carbonyl compound
- Ozonolysis: Alkene → carbonyl compounds
- Baeyer test: Alkene/alkyne decolourises alkaline KMnO₄
- Ammoniacal AgNO₃: Terminal alkyne gives silver acetylide
- Br₂/CCl₄: Unsaturation test
- Grignard + nitrile: → ketone after hydrolysis
- Nitrile hydrolysis: → carboxylic acid under complete hydrolysis
ans of all only ans
ANSWER KEY — 50 MARKS
- B
- A
- B
- C
- A
- D
- B
- B
- B
- B
- C
- A
- B
- B
- C
- A
- C
- C
- C
- A
- A
- C
- 1-bromopropane; Anti-Markovnikov rule; free-radical mechanism
- A–1, B–2, C–3, D–4
- (i) Vicinal dibromoalkane (ii) Silver acetylide precipitate (iii) Vicinal diol
- RMgX + R′CN → R′C(=N MgX)R →[H₃O⁺] R′COR; ketone; nitrile carbon becomes carbonyl carbon
- (i) CH₂=CH₂ (ii) CH₃CH₂OH (iii) CH₂=CH₂
- (i) 3-hydroxybutanal (aldol) (ii) C₆H₅CH₂OH + C₆H₅COONa (Cannizzaro)
- (i) w = −nRT ln(V₂/V₁) (ii) w = −Pext(V₂−V₁)
- Heat capacity = q/ΔT; Specific heat = q/(mΔT); Molar heat capacity = q/(nΔT)
- ΔH = ΔU + Δn(g)RT
- 42,000 J = 42 kJ
- B
- −393.5 kJ mol⁻¹
- ΔS < 0