Hydrocarbon JEE/NEET Test Paper SET-1

Hydrocarbons form the fundamental backbone of Organic Chemistry, consisting only of carbon and hydrogen atoms.
They are broadly classified into alkanes, alkenes, alkynes, and aromatic hydrocarbons based on bonding and structure.
Understanding their properties and reactions is crucial for mastering concepts in competitive exams like JEE and NEET.
This test paper is designed to evaluate conceptual clarity, problem-solving ability, and application skills.
It covers important topics such as nomenclature, isomerism, and reaction mechanisms of hydrocarbons.

  1. Arrange the following alkenes in order of their stability

2. But-2-yne and hydrogen (one mole each) are separately treated with (i) P d / C and (ii) N a / liq. N H 3 to give the products X and Y respectively

Identify the incorrect statements.

A. X and Y are stereoisomers.

B. Dipole moment of X is zero

C. Boiling point of X is higher than Y .

D. X and Y react with O 3 / Z n + H 2 O to give different products.

Choose the correct answer from the options given below :

(1) B and C only

(2) B and D only

(3) A and B only

(4) A and C only

3.

The product Y formed is :

(1) 2-methylhex-2-yne

(2) 5-methylhex-2-yne

(3) 2-methylhex-3-yne

(4) Isopropylbut-1-yne

4

5. Which compound would give 3-methyl-6- oxoheptanal upon ozonolysis ?

6. Given below are two statements :

Statement (I) : Neopentane forms only one monosubstituted derivative.

Statement (II) : Melting point of neopentane is higher than n-pentane.

In the light of the above statements, choose the most appropriate answer from the options given below :

(1) Statement I is correct but Statement II is incorrect

(2) Both Statement I and Statement II are correct

(3) Both Statement I and Statement II are incorrect

7. Total number of sigma (σ) and pi(π) bonds respectively present in hex-1-en-4-yne are:

(1) 13, 3

(2) 14, 3

(3) 3, 14

(4) 14, 13

8. Identify product [A], [B] and [C] in the following reaction sequence.

9.Statement I : Nitration of benzene involves the following step –

Statement II: Use of Lewis base promotes the electrophilic substitution of benzene. In the light of the above statements, choose the most appropriate answer from the options given below :

(1) Both Statement I and Statement II are incorrect

(2) Statement I is correct but Statement II is incorrect (3) Both Statement I and Statement II are correct (4) Statement I is incorrect but Statement II is correct

10.Compound A formed in the following reaction reacts with B gives the product C. Find out A and B

11. Product ‘A’ of following sequence of reactions is

12

A) Cyclohexanol
B) Hexane-1,6-dioic acid (Adipic acid)
C) Cyclohexanone
D) 1,2-diol (Glycol)

13.Consider the following reaction :

Which of these reaction(s) will not produce Saytzeff product ?

Which of these reaction(s) will not produce Saytzeff product ? (

1) (c) only

(2) (a) (c) and (d)

(3) (d) only

(4) (b) and (d)

15. In the following skew conformation of ethane, H’–C–C–H” dihedral angle is :

In the following skew conformation of ethane, H’–C–C–H” dihedral angle is :

(1) 120º

(2) 58º

(3) 151º

(4) 149º

Organic Reagents MCQs (NEET/JEE Practice) set 1/level NCERT

This question set is designed to strengthen key concepts of Organic Chemistry, especially reactions involving amines, diazonium salts, and important named reactions frequently asked in NEET and JEE. It covers a wide range of reagent-based transformations to help students improve accuracy and reaction recognition skills. Practice these questions regularly to build a strong conceptual foundation and boost exam confidence

1.

Nitrile on reduction gives:
A) Alcohol
B) Aldehyde
C) Primary amine
D) Secondary amine


2.

Amide + Br₂/NaOH gives:
A) Same carbon amine
B) One carbon higher amine
C) One carbon lower amine
D) Alcohol


3.

Which reagent converts alkyl halide to nitrile?
A) KOH
B) AgCN
C) KCN
D) NH₃


4.

Reduction of isocyanide gives:
A) Primary amine
B) Secondary amine
C) Tertiary amine
D) Alcohol


5.

Nitrile hydrolysis produces:
A) Alcohol
B) Aldehyde
C) Carboxylic acid
D) Amine


6.

Carboxylic acid reacts with NH₃ to give:
A) Ester
B) Amide
C) Amine
D) Nitrile


7.

Primary amine + HNO₂ gives:
A) Alkene
B) Alcohol
C) Nitrile
D) Amide


8.

Aniline + HNO₂ (0–5°C) forms:
A) Nitrobenzene
B) Diazonium salt
C) Phenol
D) Benzene


9.

C₆H₅N₂⁺Cl⁻ + KI gives:
A) Chlorobenzene
B) Bromobenzene
C) Iodobenzene
D) Fluorobenzene


10.

Sandmeyer reaction involves:
A) HNO₃
B) Cu salts
C) KMnO₄
D) NaBH₄


11.

C₆H₅N₂Cl + H₂O (warm) gives:
A) Benzene
B) Phenol
C) Aniline
D) Nitrobenzene


12.

C₆H₅N₂Cl + H₃PO₂ gives:
A) Phenol
B) Benzene
C) Aniline
D) Chlorobenzene


13.

C₆H₅N₂Cl + HBF₄ / heat gives:
A) Chlorobenzene
B) Bromobenzene
C) Fluorobenzene
D) Iodobenzene


14.

LiAlH₄ reduces CH₃COOH to:
A) Aldehyde
B) Primary alcohol
C) Ketone
D) Secondary alcohol


15.

Aldehyde reduction gives:
A) Secondary alcohol
B) Primary alcohol
C) Ketone
D) Acid


16.

Ketone reduction gives:
A) Primary alcohol
B) Secondary alcohol
C) Tertiary alcohol
D) Acid


17.

Carbylamine test is given by:
A) Primary amine
B) Secondary amine
C) Tertiary amine
D) Amide


18.

Aniline + Br₂/H₂O gives:
A) Monobromo
B) Dibromo
C) 2,4,6-tribromoaniline
D) No reaction


19.

Aniline nitration gives mainly:
A) Meta product
B) Ortho + para + some aniline
C) Only para
D) Only ortho


20.

Aniline + acetic anhydride forms:
A) Benzamide
B) Acetanilide
C) Nitrobenzene
D) Phenol


21.

Acetanilide + Br₂/CH₃COOH gives:
A) Ortho product
B) Para product
C) Meta product
D) Mixture


22.

Gabriel phthalimide synthesis gives:
A) Primary amine
B) Secondary amine
C) Tertiary amine
D) Amide


23.

Nitrile partial hydrolysis gives:
A) Acid
B) Amide
C) Amine
D) Alcohol


24.

Aniline + conc. H₂SO₄ gives:
A) Nitrobenzene
B) Sulphanilic acid
C) Phenol
D) Benzene


25.

Coupling reaction of diazonium salt gives:
A) Alcohol
B) Azo dye
C) Acid
D) Alkene

Answers:

1-C, 2-C, 3-C, 4-B, 5-C, 6-B, 7-B, 8-B, 9-C, 10-B, 11-B, 12-B, 13-C, 14-B, 15-B, 16-B, 17-A, 18-C, 19-B, 20-B, 21-B, 22-A, 23-B, 24-B, 25-B