Final Answers (with JEE/NEET Hints)

Q.	Major Product	Hint
1	2-Methylpropene (\mathbf{CH_2=C(CH_3)_2})	3° alkyl halide + strong base (CH₃O⁻) ⇒ E2 elimination (SN2 impossible).
2	tert-Butyl methyl ether (\mathbf{(CH_3)_3COCH_3})	Williamson ether synthesis: keep the bulky group as alkoxide and use methyl halide for SN2.
3	2-Chloro-2-methylbutane	HCl + 2° alcohol → carbocation → 1,2-hydride shift → 3° carbocation → Cl⁻ attack.
4	2-(Chloromethyl)tetrahydrofuran (THF–CH₂Cl)	SOCl₂ replaces only –OH by –Cl. Ether ring remains unchanged.
5	Bromocyclohexane	Cyclopentylmethyl carbocation undergoes ring expansion (5 → 6 membered) before Br⁻ attack.
6	2-Chloro-2-methylbutane	Same as Q3: hydride shift gives a more stable 3° carbocation.
7	2-Bromo-2,3-dimethylbutane	2° carbocation → 1,2-methyl shift → 3° carbocation → Br⁻ attack.
8	1-Chloro-1-phenylethane (\mathbf{C_6H_5CH(Cl)CH_3})	Benzylic rearrangement forms a stable benzylic carbocation, then Cl⁻ attacks.

One-line Revision Tricks

• 3° RX + strong base → Elimination (E2).
• Williamson Ether: RO⁻ + CH₃X/1° RX → Ether (SN2).
• HX + alcohol → Always check for carbocation rearrangement (hydride/methyl shift).
• Cyclobutylmethyl & Cyclopentylmethyl carbocations → Think ring expansion.
• SOCl₂ converts only –OH to –Cl; ethers are unaffected.

Final Answers

Please upload a clearer image of Questions 7 and 9 (or type the reagents), and I’ll draw the exact products.

Final Answers

Q.	Product
1	R–Br + CO₂ + AgBr
2	No reaction
3	1-Chloro-1-methylcyclohexane
4	1-Chloro-1-methylcyclohexane
5	trans-1,2-Dibromide (anti addition)
6	2-Bromo-2-methylpentane
7	Need reagent (not visible)
8	tert-Butylbenzene
9	Intramolecular Friedel–Crafts cyclization (exact structure unclear)