CBSE Class 12 Physics – Einstein’s Photoelectric Equation

1. State Einstein’s photoelectric equation. (1 Mark)

Answer:Kmax=hνϕ0K_{\max} = h\nu – \phi_0

where:

  • KmaxK_{\max}=Maximum kinetic energy of photoelectrons
  • h = Planck’s constant
  • ν = Frequency of incident light
  • ϕ0\phi_0 = Work function of the metal

2. What is the work function? (1 Mark)

Answer:
The work function (ϕ0​) is the minimum energy required to remove an electron from the surface of a metal.


3. Define threshold frequency. (1 Mark)

Answer:
The minimum frequency of incident radiation required to cause photoelectric emission is called the threshold frequency ν0=ϕ0h\nu_0=\frac{\phi_0}{h}


4. Why does increasing intensity not increase the maximum kinetic energy of photoelectrons? (2 Marks)

Answer:

  • The energy of each photon depends only on its frequency (E=hν).
  • Increasing intensity increases only the number of photons, not the energy of each photon.
  • Hence, the maximum kinetic energy of photoelectrons remains unchanged.

5. Why is there no photoelectric emission below the threshold frequency? (2 Marks)

Answer:
When ν<ν0\nu < \nu_0hν<ϕ0h\nu < \phi_0

The photon energy is less than the work function, so electrons cannot escape from the metal surface regardless of the intensity of light.


6. How does Einstein’s theory explain the effect of intensity? (2 Marks)

Answer:

  • Intensity is proportional to the number of incident photons.
  • More photons eject more electrons.
  • Therefore, photoelectric current increases, while the maximum kinetic energy remains unchanged.

7. Explain why photoelectric emission is instantaneous according to Einstein’s theory. (2 Marks)

Answer:
Each electron absorbs the energy of a single photon in one step. If the photon energy exceeds the work function, the electron is emitted immediately. Hence, there is no time lag.


8. Write the relation between stopping potential and frequency. (2 Marks)

Answer:eV0=hνϕ0eV_0=h\nu-\phi_0

orV0=heνϕ0eV_0=\frac{h}{e}\nu-\frac{\phi_0}{e}


9. Draw the graph of stopping potential versus frequency and write its significance. (3 Marks)

Answer:

  • The graph is a straight line.
  • Slope = he\frac{h}{e}
  • X-intercept = Threshold frequency (ν0)(\nu_0)
  • Y-intercept = ϕ0e-\frac{\phi_0}{e}

10. State any four conclusions of Einstein’s photoelectric theory. (3 Marks)

Answer:

  1. Light consists of photons.
  2. Energy of each photon is hνh\nuhν.
  3. One photon transfers its energy to one electron.
  4. Photoelectric emission occurs only if νν0\nu \ge \nu_0ν≥ν0​.
  5. Maximum kinetic energy depends only on frequency.
  6. Photoelectric current depends on intensity.

Most Important Board Formulae

  • E=hνE=h\nu
  • Kmax=hνϕ0K_{\max}=h\nu-\phi_0
  • ϕ0=hν0\phi_0=h\nu_0
  • ν0=ϕ0h\nu_0=\frac{\phi_0}{h}
  • eV0=hνϕ0eV_0=h\nu-\phi_0
  • V0=heνϕ0eV_0=\frac{h}{e}\nu-\frac{\phi_0}{e}

These are the most frequently asked CBSE Class 12 board questions from Einstein’s Photoelectric Equation.

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