CIP priority rules

R and S Configuration (JEE/NEET Concept – Easy Explanation)

R/S configuration is used to describe the absolute configuration of a chiral carbon (asymmetric carbon with 4 different groups)

Step-by-Step Rules (Cahn–Ingold–Prelog Rules)

Step 1: Assign Priority (1 → 4)

  • Higher atomic number = higher priority
  • Example:
    I > Br > Cl > S > O > N > C > H

If same atom, move to next atoms (tie-breaker rule)

Step 2: Orient the Molecule

  • Keep the lowest priority group (4) away from you (behind the plane)

Step 3: Trace Path (1 → 2 → 3)

  • Clockwise direction → R (Rectus)
  • Anticlockwise direction → S (Sinister)

Important Shortcut

If the lowest priority (4) is towards you (front):

  • Reverse the result
    • Clockwise → S
    • Anticlockwise → R

Key Points for Exams

  • R/S is about 3D arrangement, not optical rotation (+/−)
  • Always check lowest priority position
  • Double/triple bonds are treated as multiple single bonds

Quick Trick (Exam Speed)

“4 behind → direct result“4 in front → reverse result”

The R and S configuration for each stereogenic centre in this from top to bottom is:

A.R, R, R
B.R, S, S
C.R, S, R
D.S, S, R

The correct option is (C)

The R and S Configuration Practice Problems

(i)

Groups: OH, CHO, CH₂OH, H
Priority: OH (1) > CHO (2) > CH₂OH (3) > H (4)

  • H is horizontal (front) → ❗reverse result
  • 1 → 2 → 3 = anticlockwise → reversed → R

✔️ Answer: (i) → R

(ii)

Groups: OH, COOH, CH₃, H
Priority: OH (1) > COOH (2) > CH₃ (3) > H (4)

  • H is horizontal (front) → ❗reverse
  • 1 → 2 → 3 = clockwise → reversed → S

✔️ Answer: (ii) → S

(iii)

Groups: NH₂, COOH, CH₃, H
Priority: NH₂ (1) > COOH (2) > CH₃ (3) > H (4)

  • H is horizontal (front) → ❗reverse
  • 1 → 2 → 3 = anticlockwise → reversed → R

✔️ Answer: (iii) → R

(iv) (Two chiral centers)

🔹 Upper carbon

Priority: NH₂ (1) > COOH (2) > lower C (3) > H (4)

  • H is horizontal → reverse
  • 1 → 2 → 3 = anticlockwise → reversed → R

🔹 Lower carbon

Priority: OH (1) > upper C (2) > CH₃ (3) > H (4)

  • H is horizontal → reverse
  • 1 → 2 → 3 = clockwise → reversed → S

✔️ Answer: (iv) → (R, S)

Final Answers:

  • (i) → R
  • (ii) → S
  • (iii) → R
  • (iv) → (R, S)