Step 1: Calculate DU

Formula:$$DU = \frac{2C + 2 – H}{2}$$

For C₆H₁₄O (ignore O in DU):$$DU = \frac{2(6) + 2 – 14}{2} = \frac{12 + 2 – 14}{2} = 0$$

---

Meaning of DU = 0

• No double bond
• No triple bond
• No ring

So, all structures are open-chain saturated alcohols